Bond rearrangement in double
and triple ionization of H2O
F7+ + H2O at 1 MeV/amu
Results:
H2+ + O+
H2+ + O3+
=  0.209 0.006 %
=  I’ll get around to it
H+ + OH+
H+ + OH+
H2+ + O2+
=  0.067 0.003 %
H+ + OH+