Bond rearrangement in double
and triple ionization of H
2
O
F
7+
+ H
2
O at 1 MeV/amu
Results:
H
2
+
+ O
+
H
2
+
+ O
3+
=
0.209
0.006 %
=
I’ll get around to it
H
+
+ OH
+
H
+
+ OH
+
H
2
+
+ O
2+
=
0.067
0.003 %
H
+
+ OH
+